Q. A point charge + q is placed at the midpoint of a cube of side L. The electric flux emerging from the cube is
JamiaJamia 2006
Solution:
From Gauss theorem, the electric flux $ (\phi ) $ through any closed surface is equal to $ \frac{1}{{{\varepsilon }_{0}}} $ times the net charge q enclosed by the surface. Thus,
$ \phi =\int{\overrightarrow{E}}.dA=\frac{q}{{{\varepsilon }_{0}}} $
