Question

A planet is moving in a circular orbit. It completes $2$ revolutions in $360$ days. What is its angular frequency?

• A. $1.5 \times 10^{-2}$ rad / day
• B. $2.5 \times 10^{-2}$ rad / day
• C. $3.5 \times 10^{-2}$ rad / day
• D. $4.5 \times 10^{-2} $ rad / day

Answer 1

Answer: (C)

Planet completes $2$ rounds in $360$ days,
$\Rightarrow 2 \times 2 \pi$ rad in $360$ days
So, angular frequency $=\frac{\text { angle }}{\text { time }}=\frac{4 \pi}{360}$
$=3.5 \times 10^{-2} $ rad / day