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  4. A plane is inclined at an angle α = 30° with a respect to the horizontal. A particle is projected with a speed u = 2 ms-1 from the base of the plane, making an angle q = 15° with respect to the plane as shown in the figure. The distance from the base, at which the particle hits the plane is close to: (Take g = 10 ms-2)

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Q. A plane is inclined at an angle $\alpha = 30^{\circ}$ with a respect to the horizontal. A particle is projected with a speed $u = 2 ms^{-1}$ from the base of the plane, making an angle $q = 15^{\circ}$ with respect to the plane as shown in the figure. The distance from the base, at which the particle hits the plane is close to :
(Take $g = 10 \; ms^{-2}$)Physics Question Image

JEE MainJEE Main 2019Motion in a Plane

Solution:

$t = \frac{2\times2\times\sin 15^{\circ}}{g \cos 30^{\circ}} $
$ S= 2 \cos 15^{\circ} \times t - \frac{1}{2} g \sin30^{\circ} t^{2} $
Put values and solve
S $\simeq$ 20cm