Thank you for reporting, we will resolve it shortly
Q.
A piston is performing S.H.M. in the vertical direction with a frequency of 0.5 Hz. A block of 10 kg is placed on the piston. The maximum amplitude of the system such that the block remains in contact with the piston is
$f=0.5 Hz$
$\omega=2 \pi f=\pi$
for block to remain in contact with the piston at amplitude position weight A the block = Force due to oscillation.
mg = ma
$mg=m\left(\omega^{2}A\right)$
$A=\frac{g}{\omega^{2}}=\frac{10}{\pi^{2}}=1 m$