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  4. A pipe of length 20 cm is closed at one end. Which harmonic mode of the pipe is resonantly excited by a 425 Hz sources. (Speed of sound in air .=340 m s -1)

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Q. A pipe of length 20 cm is closed at one end. Which harmonic mode of the pipe is resonantly excited by a 425 Hz sources. (Speed of sound in air $\left.=340 \,m \,s ^{-1}\right)$

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Solution:

$\frac{(2 n+1) v}{4 l}=v$
$\frac{(2 n+1) 340}{4(0.2)}=425$
$ \Rightarrow (2 n+1)=\frac{425 \times 0.8}{340}=1$