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Q. A piece of wood from a recently cut tree shows 20 decays per minute. A wooden piece of same size placed in a museum (obtained from a tree cut many years back) shows 2 decays per minute. If half life of C14 is 5730 years, then age of the wooden piece placed in the museum is approximately :

JEE MainJEE Main 2014Nuclei

Solution:

use, $A =\frac{ A _{0}}{2^{ n }}, n =\frac{ t }{ T }=\frac{ t }{5730}$
$2=\frac{20}{2^{ n }}, \quad \frac{ t }{ T } \log 2=\log 10 $
or $ t =\frac{5730}{0.3010}=19039 $ year