Question

A piece of wax weighs $18.03\, g$ in air. A piece of metal is found to weigh $17.03\, g$ in water. It is tied to the wax and both together weigh $15.23\, g$ in water. Then, the specific gravity of Wax is :

• A. $ \frac{18.03}{17.03} $
• B. $ \frac{17.03}{18.03} $
• C. $ \frac{18.03}{19.83} $
• D. $ \frac{15.03}{17.83} $

Answer 1

Answer: (C)

Weight of wax in air,
$W_{a}=18.03\, g$
Weight of metal piece in water
$=17.03\, g$
Weight of metal piece and wax in water
$=15.23\, g$
Weight of wax in water
$W_{w}=15.23-17.03=-1.8\, g$
Therefore, specific gravity of wax
$=\frac{\text { weight of wax in air }}{\text { weight of wax in air - weight of wax in water }}$
$=\frac{18.03}{18.03-(-1.8)}$
$=\frac{18.03}{19.83}$