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Q. A photon of energy 2.5 eV and wavelength $\lambda$ falls on a metal surface and the ejected electrons have velocity v. If the $\lambda$ of the incident light is decreased by 20%, the maximum velocity of the emitted electrons is doubled. The work function of the metal is

Dual Nature of Radiation and Matter

Solution:

$\frac{\nu^2_1}{\nu_2^2} = \frac{\frac{hc}{\lambda_1} - \omega}{\frac{hc}{\lambda_2} - \omega}$
use $E = \frac{12400}{\lambda(A^0)} $