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Physics
A person near point of vision is 100 cm. Then, the power of lens he must wear so as to have normal vision is
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Q. A person near point of vision is $100\, cm$. Then, the power of lens he must wear so as to have normal vision is
Manipal
Manipal 2015
A
-3 D
B
+ 3 D
C
-1 D
D
+1 D
Solution:
$f =\frac{ yD }{ y - D }=\frac{100 \times 25}{100-25}$
$=\frac{100}{3} cm =\frac{1}{3} m$
$P =\frac{1}{ f }=+3\, D$