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Q. A person has a minimum distance of distinct vision as $50\,cm $ . The power of lenses required to read a book at a distance of $ 25\,cm $ is

J & K CETJ & K CET 2013Ray Optics and Optical Instruments

Solution:

$\frac{1}{f}=\frac{1}{v}-\frac{1}{u}$
$=-\frac{2}{50}+\frac{1}{25}=\frac{-1+2}{50}$
$\frac{1}{f}=\frac{1}{50}$
$\Rightarrow f=50\, cm$
$P=\frac{100}{50}=2\, D$