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  4. A perfect gas goes from state A to state B by absorbing 8×105 J of heat and doing 6.5×105 J of external work. It is now transferred between the same two states in another process in which it absorbs 105 J of heat. In the second process

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Q. A perfect gas goes from state A to state B by absorbing $8\times10^5 J$ of heat and doing $6.5\times10^5 J$ of external work. It is now transferred between the same two states in another process in which it absorbs $10^5 J$ of heat. In the second process

Thermodynamics

Solution:

$dU = dQ - dW =\left(8 \times 10^{5}-6.5 \times 10^{5}\right)=1.5 \times 10^{5} J $
$dW = dQ - dU =10^{5}-1.5 \times 10^{5}=-0.5 \times 10^{5} J$
- ve sign indicates that work done on the gas is $0.5 \times 10^{5} J$