We know for perfect gas
$V \propto T$
Here, $\frac{V_{1}}{V_{2}}=\frac{T_{1}}{T_{2}}$...(i)
According to question,
$V_{1}=V$ then $V_{2}=2V$ and $T_{1}=300\, K$
$\therefore \frac{1}{2} =\frac{300}{T_{2}}$
$T_{2} =600\, K$
$T_{2} =327^{\circ}\, C$
So, $\Delta t=327-27=300^{\circ}\, C$