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Q. A pendulum is suspended by a string of length $250 \,cm$. The mass of the bob of the pendulum is $200 \, g$. The bob is pulled aside until the string is at $60^{\circ}$ with vertical as shown in the figure. After releasing the bob. the maximum velocity attained by the bob will be _______$ms ^{-1}$.
(if $g=10 \,m / s ^{2}$ )Physics Question Image

JEE MainJEE Main 2022Work, Energy and Power

Solution:

$V _{\max }=\sqrt{2 gh }$
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The speed will be highest at the lowest position.
$ h =\left(\ell-\ell \cos 60^{\circ}\right)=\frac{\ell}{2} $
$ V _{\max }=\sqrt{2 \times g \times \frac{\ell}{2}}=\sqrt{10 \times 2.5}=5 \,m / s$