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Q.
A pebble is dropped into a well of depth $h$. The splash is heard after time $t$. If $c$ be the velocity of sound, then
Motion in a Straight Line
Solution:
To go down, the stone takes a time $t_{1}$,
Using, $s=u t+a t^{2} ; h=\left(0 \cdot t_{1}\right)+\frac{1}{2} g t_{1}^{2}$
$\Rightarrow t_{1}=\sqrt{\frac{2 h}{g}}$
The sound takes a time $t_{2}=\frac{h}{c}$ to reach back to the ear
Total time taken $=\left(t_{1}+t_{2}\right)=\sqrt{\frac{2 h}{g}}+\frac{h}{c}$