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Q. A particular station of All India Radio, New Delhi, broadcasts on a frequency of $1,368\, kHz$ (kilohertz). The wavelength of the electromagnetic radiation emitted by the transmitter is : [speed of light, $\left.c=3.0 \times 10^{8} ms ^{-1}\right]$

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Solution:

Wavelength $(\lambda)=\frac{c}{v}$
$c$ is speed of light
$v$ is frequency
$ \lambda=\frac{3 \times 10^{8}}{1368 \times 10^{3}}=219.298 m =219.3 m $