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  4. A particle starts moving with acceleration 2 m / s 2 . Distance travelled by it in 5th half second is

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Q. A particle starts moving with acceleration $2\, m / s ^{2} .$ Distance travelled by it in $5^{th}$ half second is

Motion in a Straight Line

Solution:

$S_{2.5}-S_{2}=?$ (distance travelled in $5^{th}$ half second)
$S_{2.5}=u t+\frac{1}{2} a t^{2}$
$a=2\, ms ^{-2}$
image
$\Rightarrow S_{2.5}=\frac{1}{2} \times 2 \times(2.5)^{2}=6.25\, m$
$(\because u=0)$
$S_{2}=\frac{1}{2} \times 2 \times 4=4\, m$
So, $S_{2.5}-S_{2}=2.25\, m$