Question

A particle starting from rest, moves in a circle of radius 'r'. It attains a velocity of V₀ m/s in the $n^{th}$ round. Its angular acceleration will be :-

• A. $\frac{\vee_{0}}{n}rad / s^{2}$
• B. $\frac{\vee^{2}_{0}}{2\pi nr^{2}}rad / s^{2}$
• C. $\frac{\vee^{2}_{0}}{4\pi nr^{2}}rad / s^{2}$
• D. $\frac{\vee^{4}_{0}}{4\pi nr}rad / s^{2}$

Answer 1

Answer: (C)

$\theta = (2\pi n), \omega_0 = 0, \omega = V_0/r$
$\alpha = \frac{\omega^2 - \omega_0^2}{2\theta} = \frac{(V_0/r)^2 - 0}{2(2\pi n)}$
$= \frac{V_0^2}{4\pi nr^2}$