1. Tardigrade
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  4. A particle P starts from the point z0=1+2 i, where i =√-1. It moves first horizontally away from origin by 5 units and then vertically away from origin by 3 units to reach a point z1 . From z1 the particle moves √2 units in the direction of the vector hati+ hatj and then it moves through an angle (π/2) in anticlockwise direction on a circle with centre at origin, to reach a point z2. The point z2 is given by

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Q. A particle $P$ starts from the point $z_{0}=1+2 i$, where $i =\sqrt{-1}$. It moves first horizontally away from origin by $5$ units and then vertically away from origin by $3$ units to reach a point $z_{1} .$ From $z_{1}$ the particle moves $\sqrt{2}$ units in the direction of the vector $\hat{i}+\hat{j}$ and then it moves through an angle $\frac{\pi}{2}$ in anticlockwise direction on a circle with centre at origin, to reach a point $z_{2}$. The point $z_{2}$ is given by

JEE AdvancedJEE Advanced 2008

Solution:

$z _{0} \equiv(1+2 i )$
$z _{1} \equiv(6+5 i )$
$z _{2} \equiv(-6+7 i )$