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Q. A particle of mass m moving with velocity v strikes a stationary particle of mass 2 m and sticks to it. The speed of the system will be:

JIPMERJIPMER 2001Work, Energy and Power

Solution:

Applying law of conservation of momentum $ m\upsilon =(m+2m)\,{{\upsilon }_{1}} $ so, $ {{\upsilon }_{1}}=\frac{\upsilon }{3} $