Question

A particle of mass m moves in a circular path radius r under the action of a force $ \frac{mv_{2}}{r}. $ The work done during its motion over half of the circumference of the circular path will be

• A. $ \left( \frac{mv^{2}}{r} \right)\times 2\pi r $
• B. $ \left( \frac{mv^{2}}{r} \right)\times \pi r $
• C. $ \frac{(2\pi r)}{\left( \frac{mv^{2}}{r} \right)} $
• D. zero

Answer 1

Answer: (D)

Work done by centripetal force is always zero.