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Q. A particle of mass $m$, charge $Q$ and kinetic energy $T$ enters a transverse uniform magnetic field $\vec{B}$. After $3$ seconds the kinetic energy of the particle will be

JIPMERJIPMER 2012Moving Charges and Magnetism

Solution:

When a charged particle having a given K.E, $T$ enters in a field of magnetic induction, which is perpendicular to its velocity, it takes a circular trajectory. It does not increase in energy, therefore $T$ is the K.E.