Question

A particle of mass 10 g is executing simple harmonic motion with an amplitude of 0.5 m and periodic time of ( $ \pi /5 $ ) second. The maximum value of the force acting on the particle is

• A. 25 N
• B. 5N
• C. 2.5 N
• D. 0.5 N

Answer 1

Answer: (D)

Maximum force $ F=m{{\omega }^{2}}a $ $ =m{{\left( \frac{2\pi }{T} \right)}^{2}}a=\frac{4{{\pi }^{2}}}{{{T}^{2}}}ma $ $ =\frac{4{{\pi }^{2}}}{{{\left( \frac{\pi }{5} \right)}^{2}}}\times \frac{10}{1000}\times 0.5 $ $ =0.5\text{ }N $