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  4. A particle of mass 10-3 kg and charge 5 μ C is thrown at a speed of 20 m s-1 against a uniform electric field of strength 2 × 105 N C-1. The distance travelled by particle before coming to rest is

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Q. A particle of mass $10^{-3}\, kg$ and charge $5\,\mu C$ is thrown at a speed of $20 \,m s^{-1}$ against a uniform electric field of strength $2 \times 10^5\, N\, C^{-1}$. The distance travelled by particle before coming to rest is

Electric Charges and Fields

Solution:

$F=qE=5\times10^{-6}\times2\times10^{5}=1\,N$
Since, the particle is thrown against the field
$\therefore a=-F/m=-\frac{1}{10^{-3}}=-10^{3}\,m\,s^{-2}$
As $v^{2}-u^{2}=2as$
$\therefore 0^{2}-\left(20\right)^{2}=2\times\left(-10\right)^{3}\times s$
or $s=0.2\,m$