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Q. A particle of mass 1 kg is moving in SHM with an amplitude 0.02 m and a frequency of 60 Hz. The maximum force in newton acting on the particle is

CMC MedicalCMC Medical 2011

Solution:

Maximum force $ =m{{\omega }^{2}}a $ $ =m\times 4\pi {{\nu }^{2}}a $ $ =1\times 4{{\pi }^{2}}\times {{(60)}^{2}}\times 0.02 $ $ =288\,{{\pi }^{2}} $