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  4. A particle of charge 16 × 10-16 C moving with velocity 10 ms-1 along x-axis enters a region where magnetic field of induction vecB is along the y-axis and an electric field of magnitude 104 Vm-1 is along the negative z-axis. If the charged particle continues moving along x-axis, the magnitude of vecB is :

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Q. A particle of charge $16 \times 10^{-16}\,C$ moving with velocity $10\, ms^{-1}$ along $x$-axis enters a region where magnetic field of induction
$\vec{B}$ is along the $y$-axis and an electric field of magnitude $10^4\,Vm^{-1}$ is along the negative z-axis.
If the charged particle continues moving along $x$-axis, the magnitude of $\vec{B}$ is :

JEE MainJEE Main 2013Moving Charges and Magnetism

Solution:

Since particle is moving undeflected
So, $q_E = qvB$
$\Rightarrow B=\frac{E}{V}=\frac{10^{4}}{10}=10^{3}\,wb/m^{2}$