Question

A particle moving with a uniform acceleration along a straight line covers distance $a$ and $b$ in successive intervals of $p$ and $q$ second. The acceleration of the particle is

• A. $\frac{p q(p+q)}{2(b p-a q)}$
• B. $\frac{2(a q-b p)}{p q(p-q)}$
• C. $\frac{b p-a q}{p q(p-q)}$
• D. $\frac{2(b p-a q)}{p q(p-q)}$

Answer 1

Answer: (B)

According to problem, when
$s=a, t=p$
$\because s=u t+\frac{1}{2} f t^{2} $ (here,f= acceleration)
$\therefore a=u p+\frac{f p^{2}}{2}$.....(i)
For $s=b, t=q$
$b=u q+\frac{f q^{2}}{2}$........(ii)
After solving Eqs. (i) and (ii), we get
$f=\frac{2(a q-b p)}{p q(p-q)}$