1. Tardigrade
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  4. A particle moves on a rough horizontal ground with some initial velocity say v0. If (3/4)th of its kinetic energy is lost in friction in time t0, then coefficient of friction between the particle and the ground is:

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Q. A particle moves on a rough horizontal ground with some initial velocity say $v_{0}.$ If $\left (3/4\right)th$ of its kinetic energy is lost in friction in time $t_{0}$, then coefficient of friction between the particle and the ground is:

Work, Energy and Power

Solution:

$3 / 4^{\text {th }}$ energy is lost, i.e., $1 / 4^{\text {th }}$ kinetic energy is left.
Hence, its velocity becomes $v_{0} / 2$ under a retardation of $mmg$ in time $t_{0}$.
$\frac{v_{0}}{2}=v_{0}-\mu g t_{0}$
or $\mu=\frac{v_{0}}{2 g t_{0}}$