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  4. A particle moves along the parabolic path y=x2 +2x +2 in such a way that x component of velocity vector remain 5 ms-1 during the motion .the magnitude of acceleration of the particle in ms-2 is

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Q. A particle moves along the parabolic path $y=x^2 +2x +2$ in such a way that x component of velocity vector remain $5 ms^{-1}$ during the motion .the magnitude of acceleration of the particle in $ms^{-2}$ is

Motion in a Plane

Solution:

compare with y = tan $\theta$ x - $\frac{g}{2u^2 \, cos^2 \, \theta} x^2$