1. Tardigrade
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  3. Physics
  4. A particle is thrown up inside a stationary lift of sufficient height. The time of flight is T. Now it is thrown again with same initial speed v0 with respect to lift. At the time of second throw, lift is moving up with speed v0 and uniform acceleration g upward (the acceleration due to gravity) The new time of flight is

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Q. A particle is thrown up inside a stationary lift of sufficient height. The time of flight is $T$. Now it is thrown again with same initial speed $v_{0}$ with respect to lift. At the time of second throw, lift is moving up with speed $v_{0}$ and uniform acceleration $g$ upward (the acceleration due to gravity) The new time of flight is

Motion in a Straight Line

Solution:

With respect to lift initial speed $=v_{0}$
Acceleration $= -2 g$
Displacement $= 0$
$\therefore S=ut+\frac{1}{2}at^{2}$
$0=v_{0}T'+\frac{1}{2}\times 2g\times T'^{2}$
$\therefore T'=\frac{v_{0}}{g}=\frac{1}{2}\times\frac{2v_{0}}{g}=\frac{1}{2} T$