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  4. A particle is projected towards the north with speed 20 m/s at an angle 45o with horizontal. Ball gets horizontal acceleration of 7.5 m/s2 towards east due to wind. Range of ball (in meter) minus 42 m will be

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Q. A particle is projected towards the north with speed $20 \, m/s$ at an angle $45^{o}$ with horizontal. Ball gets horizontal acceleration of $7.5 \, m/s^{2}$ towards east due to wind. Range of ball (in meter) minus $42 \, m$ will be

NTA AbhyasNTA Abhyas 2020Motion in a Plane

Solution:

Time of flight : $T=\frac{2 u sin \theta }{g}=2\sqrt{2} \, s$
Range (along north) $=\frac{u^{2} sin 2 \theta }{g}=40 \, m$
Range (along east) $=\frac{1}{2}aT^{2}=30 \, m$
$\therefore $ Range $=\sqrt{30^{2} + 40^{2}}=50 \, m$