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Q. A particle is projected in such a way that, taking point of projection as origin, $y = 8t - 5t^2$ and $x = 6t$. What is the range of projectile?

Motion in a Plane

Solution:

For range
$y=0 \Rightarrow t=0, \frac{8}{5}$
$R=6\left(\frac{8}{5}\right)=9.6 m$