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  4. A particle is oscillating according to the equation X=7 cos 0.5 π t, where ' t ' is in second. The point moves from the position of equilibrium to maximum displacement in time (in sec)?

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Q. A particle is oscillating according to the equation $X=7 \cos 0.5 \pi t$, where ' $t$ ' is in second. The point moves from the position of equilibrium to maximum displacement in time (in $\sec$)?

Oscillations

Solution:

$x=7 \cos 0.5 \pi$
General form of equation.
$x=A \cos \omega t$
Given equation compare with standard form
$\omega=\frac{2 \pi}{T}=0.5 \pi ; T =4\, \sec$
$T'= T / 4=4 / 4=1\, \sec$