Question

A particle is oscillating according to the equation $ V(t) = 4 \,sin\, 0.4\pi\, t $ metres. In how much time after the motion begins will that particle reach the extreme position from the mean position?

• A. $ 1.25 \,s $
• B. $ 3.25 \,s $
• C. $ 4.25 \,s $
• D. $ 2.25 \,s $

Answer 1

Answer: (A)

From the given equation, $\omega=\frac{2\pi}{T}=0.4\pi $
$T=\frac{2\pi}{\omega}$
$=\frac{2\pi}{0.4\pi}=5s$
Time taken to reach extreme position from mean position
$=\frac{1}{4} T$
$\frac{5}{4}=1.25\,s$