Question

A particle is moving in a circular path and its acceleration vector is making an angle of $30^\circ $ with the velocity vector, then the ratio of centripetal acceleration to its tangential acceleration is

• A. $\frac{1}{2}$
• B. $\frac{\sqrt{3}}{2}$
• C. $\frac{1}{\sqrt{3}}$
• D. $\sqrt{3}$

Answer 1

Answer: (C)

For a body undergoing circular motion, let net acceleration makes an angle $\theta $ with the tangent, then
$tan \theta =\frac{a_{c}}{a_{t}}$
$\therefore \, \, \frac{a_{c}}{a_{t}}=tan 30^\circ =\frac{1}{\sqrt{3}}$