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  4. A particle is moving along a straight line with constant acceleration. At the end of tenth second its velocity becomes 20 m/s and in tenth second it travels a distance of 10 m. Then the acceleration of the particle will be

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Q. A particle is moving along a straight line with constant acceleration. At the end of tenth second its velocity becomes $20 \,m/s$ and in tenth second it travels a distance of $10 \,m$. Then the acceleration of the particle will be

Motion in a Straight Line

Solution:

Using $v - u + at$
$\Rightarrow 20 = u + a \times 10 \,\,...(i)$
and $s_n = u + \frac{a}{2} ( 2n - 1)$
$\Rightarrow 10 = u + \frac{a}{2} ( 2\times 10 - 1) \,\,...(ii)$
On solving (i) and (ii) we get $a = 20\, m/s^2$