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Q. A particle is dropped from a height $H$ . The de-Broglie wavelength of the particle depends on height as

NTA AbhyasNTA Abhyas 2020

Solution:

de-Broglie wavelength $\left(\lambda \right)=\frac{h}{m v}$
$\lambda =\frac{h}{m \sqrt{2 g H}}$
Hence, $\lambda \propto H^{- 1 / 2}$