Question

A particle doing S.H.M. have amplitude $5 \,cm$, mass $0.5\, kg$ and angular frequency $5$ is at $1 \,cm$ from mean position. Find potential energy and kinetic energy.

• A. K.E. $=150 \times 10^{-4} J$, P.E. $=6.25 \times 10^{-4} J$
• B. K.E. $=6.25 \times 10^{-4} J , P . E .=150 \times 10^{-3} J$
• C. K.E. $=6.25 \times 10^{-4} J$, P.E. $=6.25 \times 10^{-4} J$
• D. K.E. $=150 \times 10^{-3}$ J, P.E. $=150 \times 10^{-3} J$

Answer 1

Answer: (A)

Potential energy
U $\quad \frac{1}{2}m \,\,{}^{2}x^{2} \,\,\, \frac{1}{2} \,\,0.5\,\, 25 \,\, \left(10^{2}\right)^{2}$
$=\frac{25}{4}\times10^{-4}$ Joule = 6.25 × 10^-4 Joule
Kinetic energy
$K \frac{1}{2}m\,\,{}^{2}\left(A^{2}\,\,x^{2}\right)$
$\, =\frac{1}{2}\times0.5\times25\left[25-1\right]\times10^{-4}$
= 150 × 10^-4 joule