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  4. A parallel plate condenser with oil (dielectric constant 2) between the plates has capacitance C. lf oil is removed, the capacitance of capacitor becomes

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Q. A parallel plate condenser with oil (dielectric constant 2) between the plates has capacitance C. lf oil is removed, the capacitance of capacitor becomes

MHT CETMHT CET 2008Electrostatic Potential and Capacitance

Solution:

The capacitance of a parallel plate capacitor with dielectric (oil) between its plates is
$ C = \frac {K \varepsilon_0 A}{d} \, \, \, \, \, \, \, ...(i)$
When dielectric (oil) is removed, so capacitance
$ C_0 = \frac {\varepsilon_0 A}{d} \, \, \, \, \, \, \, ...(ii)$
Comparing Eqs. (i) and (ii), we get
$\, \, \, \, \, \, \, \, \, \, \, \, C = KC_0$
$\Rightarrow \, \, \, \, \, \, \, C_0 = \frac {C}{K} = \frac {C}{2} \, \, \, \, \, \, (\therefore k = 2)$