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Q. A parallel plate condenser with a dielectric constant $K$ between the plates has a capacity $C$ and is charged to a potential $V$ volt. The dielectric slab between the plates is slowly removed and then reinserted. The net work done by the system in this process is

Electrostatic Potential and Capacitance

Solution:

Q is constant
Case-I
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$C'=k C$
$Q=$ same
$U _{1}=\frac{ Q ^{2}}{2 C '}=\frac{ Q ^{2}}{2 kC }$
Case-II
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$C ''= C$
$Q =$ same
$U _{2}=\frac{ Q ^{2}}{2 C }$
Case-III
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$C '''= kC$
$Q =$ same
$U _{3}=\frac{ Q ^{2}}{2 k C }$
Work done $= U _{3}- u _{1} =0$