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  4. A parallel plate capacitor with plates of area 1 m2 each, area t a separation of 0.1 m. If the electric field between the plates is 100 N/C, the magnitude of charge each plate is: Take (ϵ0 = 8.85 × 10-12 (C2/N-m2))

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Q. A parallel plate capacitor with plates of area $1\,m^2$ each, area t a separation of $0.1\, m$. If the electric field between the plates is $100\, N/C$, the magnitude of charge each plate is :
Take $(\epsilon_0 = 8.85 \times \, 10^{-12} \, \frac{C^2}{N-m^2})$

JEE MainJEE Main 2019Electrostatic Potential and Capacitance

Solution:

$E =\frac{\sigma}{\epsilon_{0}}=\frac{ Q }{ A \in_{0}}$
$Q = AE \in_{0}$
$Q =(1)(100)\left(8.85 \times 10^{-12}\right)$
$Q =8.85 \times 10^{-10} C$