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  4. A parallel plate capacitor of plate area A has a charge Q. The force on each plate of the capacitor is

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Q. A parallel plate capacitor of plate area $A$ has a charge $Q$. The force on each plate of the capacitor is

Bihar CECEBihar CECE 2009Electrostatic Potential and Capacitance

Solution:

Force on one plate due to another is
$F =Q E=Q \times \frac{\sigma}{2 \varepsilon_{0}}$
$=Q\left[\frac{Q}{2 A \varepsilon_{0}}\right]$
$=\frac{Q^{2}}{2 A \varepsilon_{0}}$