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  4. A parallel plate capacitor of capacitance 5 μ F and plate separation 6 cm is connected to a 1 V battery and charged. A dielectric of dielectric constant 4 and thickness 4 cm is introduced between the plates of the capacitor. The additional charge that flows into the capacitor from the battery is

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Q. A parallel plate capacitor of capacitance $5\,\mu F$ and plate separation $6 \,cm$ is connected to a $1 \,V$ battery and charged. $A $ dielectric of dielectric constant $4$ and thickness $4 \,cm$ is introduced between the plates of the capacitor. The additional charge that flows into the capacitor from the battery is

Electrostatic Potential and Capacitance

Solution:

$\therefore $ Charge on capacitor plates now will be
$Q' = CV = 10\mu F \times 1V = 10 \mu C$
Additional charge transferred = $Q' - Q = 10 \mu\,C$
= $5 \mu C$