Question

A parallel plate capacitor of capacitance $20\mu\,F$ is being charged by a voltage source whose potential is changing at the rate of $3 \,V/s$. The conduction current through the connecting wires, and the displacement current through the plates of the capacitor, would be, respectively :

• A. $60\mu\,A$, zero
• B. zero, zero
• C. zero, $60\mu\,A$
• D. $60\mu\,A$ $60\mu\,A$

Answer 1

Answer: (D)

Capacitance of capacitor $C =20\mu F $
$ = 20 \times10^{-6} F $
Rate of change of potential $ \left(\frac{dV}{dt}\right) =3v/s$
$ q=CV $
$ \frac{dq}{dt} =C \frac{dV}{dt} $
$ i_{c} = 20\times10^{-6} \times3 $
$= 60\times10^{-6} A = 60\mu A $
As we know that $ i_{d} =i_{c} = 60 \mu A $