Q. A parallel-plate capacitor is filled by a dielectric whose relative permittivity varies with the applied voltage $(V)$ as $\varepsilon=\alpha V$ where $\alpha=3\, V ^{-1}$. A similar capacitor with no dielectric is charged to $V _{0}=52\, V$. It is then connected to the uncharged capacitor with the dielectric. What is the final voltage (in $V$) on the capacitor?
Electrostatic Potential and Capacitance
Solution: