Question

A parallel plate capacitor is charged to $100 \times 10^{-6} C$. Due to radiations falling, from a radiating source the plate loses charge at the rate of $2 \times 10^{-7} Cs ^{-1}$. The magnitude of displacement current is

• A. $10^{-6} A$
• B. $10^{-4} A$
• C. $2 \times 10^{-7} A$
• D. $2 \times 10^{-7} mCs ^{-1}$

Answer 1

Answer: (C)

Magnitude of displacement current is given by
$I_{d}=I_{C}=\left|\frac{d q}{d t}\right|=2 \times 10^{-7} Cs ^{-1}=2 \times 10^{-7} A$