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Q.
A parallel plate capacitor is charged and then disconnected from the charging battery. If the plates are now moved farther apart by pulling at them by means of insulating handles, then
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Solution:
We know that
The parallel plate capacitor $C=\frac{\varepsilon_{0} \cdot A}{d}$
When $d$ (distance between two parallel plate) increase, then $C$ will be decrease
$\because Q=C V $ where $Q=$ constant
$\therefore $ The voltage across the capacitor increases.