Q. A parallel plate capacitor has two square plates with equal and opposite charges. The surface charge densities on the plates are $ +\sigma $ and $ -\sigma $ respectively. In the region between the plates the magnitude of the electric field is
J & K CETJ & K CET 2011Electrostatic Potential and Capacitance
Solution:
The magnitude of the electric field
$ E=\frac{1}{2\varepsilon_{0}}[\sigma (-\sigma )] $
$ E=\frac{2\sigma }{2\varepsilon _{0}} $
$ E=\frac{\sigma }{\varepsilon_{0}} $
