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Q.
A parallel plate capacitor has a capacity $C$. The separation between the plates is doubled and a dielectric medium is inserted between the plates. If the capacity is $3C$, then · the dielectric constant of the medium will be
COMEDKCOMEDK 2015Electrostatic Potential and Capacitance
Solution:
Capacity ofa parallel plate capacitor, $ C =\frac{\varepsilon_0 A}{d} $ ...(i)
Whert plate separation is increased and a dielectric is' inserted, its capacity becomes $3C$.
$3C = \frac{\varepsilon_0 KA}{d'}=\frac{\varepsilon_0 KA}{2d} \:\:\:\:\: (\because \:\: d' = 2d)$
$3C = \frac{K}{2} C$ [Using eqn. (i)]
Hence, $K = 6$