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  4. A parallel plate capacitor filled with a material of dielectric constant k is charged to a certain voltage. The dielectric material is removed. Then:

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Q. A parallel plate capacitor filled with a material of dielectric constant k is charged to a certain voltage. The dielectric material is removed. Then:

EAMCETEAMCET 2004

Solution:

As capacitance of capacitor after introducing dielectric is given by $ C=\frac{k{{\varepsilon }_{0}}A}{d} $ Hence, if dielectric is introduced the capacitance increases by k, but when dielectric is removed, then capacitance will decrease by factor k and since $ V=\frac{Q}{C} $ Hence, if C decreases in factor k then V will increase by factor k.