1. Tardigrade
  2. Question
  3. Physics
  4. A parallel plate capacitor after charging is kept connected to a battery and the plates are pulled apart with the help of insulating handles. Now which of the following quantities will decrease ?

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. A parallel plate capacitor after charging is kept connected to a battery and the plates are pulled apart with the help of insulating handles. Now which of the following quantities will decrease ?

Electrostatic Potential and Capacitance

Solution:

$V$ remains constant
$C=\frac{A \varepsilon_{0}}{d}$
$ \Rightarrow d$ increases
$C $ decreases
$q=C V$
$q$ decreases
$U=\frac{1}{2} C V^{2}$
$U$ decreases